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Clausius-Clapeyron Calculator

Chemistry

ln(P₂/P₁) = −(ΔH_vap/R)·(1/T₂ − 1/T₁): vapor pressure at a new temperature, the boiling point at altitude or under pressure, or ΔH_vap from two points or a fit of your own data. A third mode handles the melting line with the full Clapeyron equation.

Mixing liquids? Raoult's Law Calculator → · Solutes raising the boiling point? Boiling Point Elevation →

Quick Examples:

Settings

Liquid ⇌ vapor: boiling and evaporation.
Water boils at 99.97 °C at 1 atm, where ΔH_vap = 40.65 kJ/mol. Critical point 373.95 °C, 220.6 bar.
Pressures and ΔH. Temperatures always show 2 decimals.

Inputs

T₂ is also shown in the other two units.
≈ 83.43 kPa (625.8 mmHg) at 1609 m, standard atmosphereWeather moves the real pressure by a few percent, about ±1 °C on water's boiling point. For a measured value, choose Absolute and enter your barometer's station pressure, not the sea-level pressure weather apps report.
Need ΔH from formation enthalpies? Enthalpy Change Calculator →

Result

T₂ (boiling point at P₂)
94.52 °C
= 367.67 K = 202.14 °F
TemperatureVapor pressure
Point 1 (reference)99.97 °C1 atm
Point 294.52 °C83.43 kPa
  • P₂/P₁ = 0.8234
  • Trouton ratio ΔH_vap/T_b = 108.9 J/(mol·K): high, as in hydrogen-bonded liquids such as water and alcohols.
  • IAPWS-IF97: water boils at 94.62 °C at this pressure. This estimate is 0.10 °C low.
  • Mixing liquids? Raoult's Law Calculator →

Boiling point vs altitude

Boiling point (°C)

Altitude (m, standard atmosphere)

Clausius-Clapeyron model

IAPWS-IF97 (measured)

Near sea level, water's boiling point drops about 1 °C for every 296 m you climb.

Step-by-Step Solution

P₂ from altitude (ISA): 101325 Pa × (1 − 0.0065 K/m × 1609 m / 288.15 K)^5.25579 = 83431.4 Pa

ln(P₂/P₁) = ln(83431.4 / 101325) = −0.194308

1/T₂ = 1/T₁ − R·ln(P₂/P₁)/ΔH_vap = 1/373.124 K − 8.314462618 × (−0.194308) / 40650 J/mol = 0.00268007 + 3.97434 × 10⁻⁵ = 0.00271982 K⁻¹

T₂ = 367.67 K = 94.52 °C

About This Tool

Clausius-Clapeyron Calculator – Vapor Pressure, Boiling Points and ΔH_vap

The Clausius-Clapeyron equation links the vapor pressure of a pure liquid (or solid) to temperature through its enthalpy of vaporization. This calculator uses it three ways: to find the vapor pressure at a new temperature or the boiling point at a new pressure, to get ΔH_vap from two points or a least-squares fit of your own data, and to follow the melting line of ice with the full Clapeyron equation. British texts write vapour pressure; the physics is the same.

Where the equation comes from

Émile Clapeyron showed in 1834 that along any phase boundary dP/dT = ΔH/(T·ΔV). In 1850 Rudolf Clausius simplified it for evaporation: the vapor's volume dwarfs the liquid's and behaves almost ideally, so ΔV ≈ RT/P. That gives d ln P/dT = ΔH_vap/(RT²), and with ΔH_vap constant, ln(P₂/P₁) = −(ΔH_vap/R)·(1/T₂ − 1/T₁).

Boiling is a pressure match

A liquid boils when its vapor pressure equals the pressure around it. Climb a mountain and the air pressure falls, so water boils colder: about 94.5 °C in Denver and below 70 °C on Everest, roughly 1 °C lower for every 300 m near sea level. A pressure cooker does the opposite: at about 15 psi gauge, water boils near 121 °C. Vacuum distillation and rotary evaporators lower the pressure until a solvent boils at a gentle bath temperature; acetone boils at 40 °C under about 590 mbar.

Reading a ln P vs 1/T plot

Plot ln P against 1/T and you get a straight line whose slope is −ΔH_vap/R. Example 2B in the Fit data mode uses seven vapor pressures between 20 and 50 °C. The fit gives ΔH_vap = 30.51 ± 0.33 kJ/mol, and extending the line to 1 atm predicts a normal boiling point of 68.72 °C, with a 95 % interval of 67.61–69.82 °C. The boiling point lies outside the measured range, and the interval widens the further you extrapolate, because any uncertainty in the slope grows with distance from the centre of the data. n-Hexane (68.73 °C) falls inside it, which makes it a candidate, not an identification.

Trouton's rule

For many liquids, ΔH_vap divided by the normal boiling point is close to 85–88 J/(mol·K), a pattern called Trouton's rule. Water's ratio is about 109 J/(mol·K). Hydrogen bonds hold the liquid in an ordered network, so escaping into the vapor gains more entropy than usual. Alcohols are high for the same reason, which is why a Trouton estimate undershoots their ΔH_vap.

When the equation breaks

The simple form assumes ΔH_vap is constant, the vapor is ideal and the liquid's volume is negligible. The first assumption fails over wide ranges: start from water's boiling point and predict its vapor pressure at 25 °C, and you overshoot the measured 3170 Pa by about 18.5 %, because ΔH_vap grows as the temperature falls. Adding the heat-capacity change ΔCp (about −42 J/(mol·K) for water) cuts the error to a few percent. Near the critical point the vapor stops behaving ideally. Data tables therefore use empirical fits such as the Antoine or Wagner equations.

Pick a nearby reference point
The closer your reference temperature is to the one you want, the less the constant-ΔH assumption matters. From the normal boiling point, Denver's boiling point comes out within 0.1 °C of the measured value.

Melting under pressure

For melting, neither phase is a gas, so the full Clapeyron equation is needed. Ice is less dense than water, so ΔV_fus is negative and pressure lowers the melting point, but only by about 0.0074 °C per bar. A skater's blade lowers it by under 0.2 °C, nowhere near enough to explain skating at −10 °C; most of the slipperiness is credited to a thin premelted surface layer and frictional heating. The classic regelation demonstration, a weighted wire that slowly cuts through a block of ice which refreezes behind it, works only because the ice is held right at 0 °C, where a small shift is enough.

Same maths, different names

The Van 't Hoff Equation Calculator does the same thing for equilibrium constants, and the Arrhenius Equation Calculator for rate constants: each is ln of something against 1/T. For mixtures, use the Raoult's Law Calculator; for heat amounts, the Latent Heat Calculator.

Frequently Asked Questions

Is the Clausius-Clapeyron Calculator free?

Yes, Clausius-Clapeyron Calculator is totally free :)

Can I use the Clausius-Clapeyron Calculator offline?

Yes, you can install the webapp as PWA.

Is it safe to use Clausius-Clapeyron Calculator?

Yes, any data related to Clausius-Clapeyron Calculator only stored in your browser (if storage required). You can simply clear browser cache to clear all the stored data. We do not store any data on server.

What is the Clausius-Clapeyron equation?

It describes how the vapor pressure of a pure liquid or solid changes with temperature: d ln P/dT = ΔH_vap/(RT²). With ΔH_vap constant it integrates to ln(P₂/P₁) = −(ΔH_vap/R)(1/T₂ − 1/T₁), so ln P is a straight line against 1/T with slope −ΔH_vap/R.

How do I find the heat of vaporization from two vapor pressures?

Choose Two points, solve for ΔH and enter both temperatures with their vapor pressures. The calculator uses ΔH_vap = −R·ln(P₂/P₁)/(1/T₂ − 1/T₁). The pressure unit doesn't matter because only the ratio enters, but each pressure must be paired with its own temperature.

How do I calculate the boiling point of water at altitude?

A liquid boils when its vapor pressure equals the air pressure, so the calculator turns your altitude into a standard-atmosphere pressure and solves for the temperature where water's vapor pressure matches it. In Denver (1609 m) water boils near 94.5 °C; near sea level the boiling point drops about 1 °C for every 300 m you climb.

Why does a pressure cooker cook food faster?

Sealing the pot raises the pressure, and water only boils once its vapor pressure reaches that higher pressure. At about 15 psi gauge (roughly 2 atm absolute) water boils near 121 °C instead of 100 °C, and chemical reactions in food run much faster at that temperature.

What is Trouton's rule, and why doesn't water follow it?

Trouton's rule says ΔH_vap/T_b is about 85–88 J/(mol·K) for many liquids at their normal boiling point. Water's ratio is about 109 J/(mol·K) because hydrogen bonds order the liquid, so boiling gains more entropy; alcohols are high for the same reason, which makes the rule underestimate their ΔH_vap.

Does the pressure of a skate blade melt the ice?

Not by much. The Clapeyron equation shows ice's melting point falls only about 0.0074 °C per bar, so a 70 kg skater on a 3 mm × 100 mm blade lowers it by under 0.2 °C. That can't explain skating at −10 °C; the slipperiness comes mostly from a thin premelted surface layer and frictional heating.