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Mass-Energy Equivalence Calculator

Physics

What are we solving?

Every mode below is E = mc² wearing a different hat. Pick the one that matches your problem; the input boxes follow.

E = mc²
The rest energy locked up in a mass at rest. Because c² is 9 × 10¹⁶, a gram is worth about 21 kilotons of TNT.
Loads a complete scenario — every field, including the ones this mode ignores.
Writes the CODATA rest mass straight into the mass box, in MeV/c².
One kilogram, fully converted
The headline number: 8.98755 × 10¹⁶ J, about 21.5 megatons of TNT, or 2.4965 × 10¹⁰ kWh.

Inputs

The mass to convert. Typed in whichever unit you pick alongside.
Applies to every mass box in this mode.
Optional. Scales the per-event energy up to a sample you can weigh.
Switch on to read the box above as moles of reactions, multiplied by Avogadro's number.
Drag to see the strictly linear mass–energy relationship. This writes the mass box, so nothing desyncs.
0 to 10. Threaded through the copy, TXT and CSV exports too.
The textbook 3 × 10⁸ m/s, for reproducing a printed answer.
Show the substitution line by line.
TNT, kWh, petrol and household-years, each with its stated basis.
Rest energy
5.6096e+23 TeV

8.9876e+16 J

≈ 21.5 megatons of TNT
Diagram of mass on the left multiplied by c squared to give energy on the right, for a mass of 1 kg.m1 kg× c²8.9876 × 10¹⁶ m²/s²8.9876e+16 JE

1 kg = 6.0221e+26 u

The same mass in kilograms and atomic mass units.

5.6096e+23 TeV

What the mass is worth standing still.

Where this energy sits

A logarithmic ruler, because these quantities span fifty decades and a linear axis would collapse everything below a kiloton into one pixel.

Logarithmic scale from 10 to the minus 20 joules to 10 to the 30 joules with reference energies marked, and the computed result of 8.9876e+16 joules highlighted.10⁻²⁰ J10³⁰ JA green photonOne chemical bondOne U-235 fissionAn AA batteryA day of human foodA lightning boltThe Hiroshima bombOne gram fully convertedOne kilogram fully convertedThe Sun, one secondyour result

The same energy in other units

UnitValue
J — joule8.9876e+16 J
kJ — kilojoule8.9876e+13 kJ
MJ — megajoule8.9876e+10 MJ
GJ — gigajoule8.9876e+7 GJ
eV — electronvolt5.6096e+35 eV
MeV — megaelectronvolt5.6096e+29 MeV
GeV — gigaelectronvolt5.6096e+26 GeV
kWh — kilowatt-hour2.4965e+10 kWh
kcal — kilocalorie2.1481e+13 kcal
t TNT — tonnes of TNT2.1481e+7 t TNT
kt TNT — kilotons of TNT21481 kt TNT
Mt TNT — megatons of TNT21.481 Mt TNT

12 units, all derived from the one unrounded joule figure — never chained one unit to the next.

What that actually means

Every benchmark states its own assumption
These are comparisons, not measurements. The household figure in particular depends entirely on what you count: the 2 700 kWh used here is typical UK domestic electricity, and counting gas as well roughly quadruples the per-home figure. The basis column shows the divisor for each row so you can substitute your own.
Equivalent toValueBasis
Tonnes of TNT2.1481e+7 t TNT

1 tonne of TNT ≡ 4.184 × 10⁹ J, the conventional definition.

Kilotons of TNT21481 kt TNT

1 kiloton ≡ 4.184 × 10¹² J.

Megatons of TNT21.481 Mt TNT

1 megaton ≡ 4.184 × 10¹⁵ J.

Kilowatt-hours2.4965e+10 kWh

1 kWh = 3.6 × 10⁶ J exactly.

Litres of petrol2.6279e+9 L

Assumes 34.2 MJ per litre — the usual lower-heating-value figure for motor gasoline. Diesel is about 10 % higher.

Household-years of electricity9.2465e+6 household-years

Assumes 2700 kWh of electricity per household per year — a typical UK domestic electricity figure. Counting gas as well roughly quadruples the per-home figure and so divides this count by about four.

Hiroshima-scale bombs1432.1 bombs

Assumes a 15 kt yield, the usual modern estimate for Little Boy.

Lightning bolts8.9876e+7 bolts

Assumes 1 GJ per typical cloud-to-ground stroke, an order-of-magnitude figure.

Step by step

Formula

E = m·c²

Substitute

E = (1 kg) × (2.99792458e+8 m/s)²

c² = 8.987551787e+16 m²/s²

Result

E = 8.987552e+16 J

How the energy scales with mass

Strictly linear — doubling the mass doubles the energy. The surprise in E = mc² was never the shape of the relationship, only its gradient.

Mass (kg)Energy (J)Kilotons of TNT
0.222221.9972e+164773.5
0.444443.9945e+169547
0.666675.9917e+1614321
0.888897.9889e+1619094
1.11119.9862e+1623868
1.33331.1983e+1728641
1.55561.3981e+1733415
1.77781.5978e+1738188
21.7975e+1742962

The constants behind every answer

SymbolQuantityValue

c

Speed of light in vacuum

299792458 m/s

The conversion factor itself

8.98755178736818e+16 m²/s²

u

Atomic mass unit

1.6605390666e-27 kg

e

Elementary charge / eV in joules

1.602176634e-19 J per eV

h

Planck constant

6.62607015e-34 J·s

N_A

Avogadro constant

6.02214076e+23 mol⁻¹

mₑc²

Electron rest energy

0.51099895 MeV

m_pc²

Proton rest energy

938.272088 MeV

1 t TNT

Tonne of TNT

4.1840e+9 J

Masses in the particle library are the CODATA values; nuclide masses in the reaction presets come from the standard atomic-mass evaluation. Where a mass unit is offered as MeV/c², it is the energy ladder divided by c², not a second table.

About This Tool

Mass-Energy Equivalence Calculator — E = mc² in Every Direction

Mass and energy are not two things that convert into one another. They are one thing, and is the exchange rate between the units we happened to invent for measuring it. This mass-energy equivalence calculator works that exchange rate in both directions and in every context it shows up: the rest energy of a mass, the mass defect and Q-value of a nuclear reaction, the relativistic energyof a moving particle, particle–antiparticle annihilation, partial conversion at a real process efficiency, and the energy–momentum invariant.

Why the number is so large

The whole subject turns on one multiplication. The speed of light is 299 792 458 m/sexactly — exactly, because since 1983 the metre has been defined from it — so c² = 8.987551787 × 10¹⁶ m²/s². A single kilogram is therefore worth 8.98755 × 10¹⁶ J, which is 21.5 megatons of TNT or 2.4965 × 10¹⁰ kWh. Nothing else in physics has a conversion factor that violent, and it is why the mass change in a chemical reaction — real, but around one part in 10¹⁰ — has never been weighed.

Mass defect, binding energy and the 931.494 shortcut

A nucleus weighs less than the sum of its nucleons. That missing mass is the binding energy, and it is what a nuclear reaction trades in. Because nuclear masses are tabulated in atomic mass units to eight or nine decimals, and a mass defect is a difference between two nearly identical numbers, the sensible route is to subtract in u first and convert once at the end: 1 u ≡ 931.494 MeV. Converting each mass to kilograms first throws away most of your significant figures to floating-point cancellation before you have even subtracted.

Deuterium–tritium fusion is the standard worked example. 2.014102 + 3.016049 = 5.030151 u of reactants against 4.002603 + 1.008665 = 5.011267 u of products leaves Δm = 0.018884 u, so Q = 17.590 MeVper reaction. Scaled by Avogadro’s number that is 1.697 × 10⁹ kJ/mol, and per kilogram of fuel 3.374 × 10¹⁴ J/kg— all from converting just 0.375 % of the reactant mass. A negative defect is not an error; it means the products are heavier and the reaction is endothermic, so the calculator labels it as energy absorbed rather than rejecting it.

The two mistakes that cost the most marks
Forgetting to square c— which is off by a factor of 300 million — and mixing atomic mass units with grams. A periodic table’s “grams per mole” figure is already the mass in u; it needs no conversion at all. This tool normalises every input to SI before any arithmetic runs and converts back only at the display boundary, which removes that entire class of error.

Once the particle moves

For a moving particle the rest energy is only part of the story. The Lorentz factor γ = 1/√(1 − β²) scales it up to a total energy E = γm₀c², leaving KE = (γ − 1)m₀c² as the kinetic part and p = γm₀v as the momentum. An electron at 0.99c has γ = 7.0888, E = 3.6224 MeV, KE = 3.1114 MeV and p = 3.58616 MeV/c— a figure some sources misprint as 3.5878, and one the invariant pc = √(E² − (m₀c²)²) settles independently.

At everyday speeds the direct subtraction in γ − 1 is numerically hopeless: for an airliner γ differs from 1 in the thirteenth decimal place, and double-precision arithmetic has already run out of digits. The calculation switches to the series β²/2 + 3β⁴/8 + … below β = 10⁻³, which reproduces ½mv² to full precision and shows why the classical formula was never wrong, merely truncated.

The invariant, and the massless case

E² = (pc)² + (m₀c²)² holds for every particle in every frame. Leave any one of the three blank and it is solved for: a proton with 500 MeV/c of momentum has E = √(500² + 938.272²) = 1063.181 MeV and so KE = 124.909 MeV. Set m₀ = 0 and the relation collapses to E = pc, the photon case — momentum without rest mass, always travelling at exactly c.

Relativistic mass is a retired idea
Calling γm₀a “mass” suggests an object genuinely gets heavier, and that Newton’s second law still works with it substituted in. Neither is true — the notion breaks down entirely for a force applied along the direction of motion. Modern practice is that mass means rest mass, one invariant number, with all the velocity dependence living in the energy and momentum instead. The figure is shown here only because older textbooks still quote it.

Annihilation, efficiency and honest comparisons

An electron and a positron at rest convert entirely: 1.022 MeV total, emitted as two back-to-back 511 keV gamma photons at λ = 2.4263 pm. That is the coincidence signal every PET scanner is built to detect, and read backwards it is the pair-production threshold. Real energy sources are far less thorough: fission converts about 0.09 % of its fuel mass, giving 8.09 × 10¹³ J— 22.5 GWh — from a kilogram of uranium, solar fusion about 0.7 %, and chemical burning around 10⁻¹⁰.

The everyday-equivalence panel exists to make those magnitudes intuitive, and every row carries the figure it divides by. Some are definitions and exact — a tonne of TNT is 4.184 × 10⁹ J, a kilowatt-hour is 3.6 × 10⁶ J. Others are stated assumptions: 34.2 MJ per litre of petrol, a 15 kt Hiroshima yield, and 2 700 kWh of electricity per household per year. That last one is worth reading carefully, because household energy claims are routinely quoted without a basis: 2 700 kWh is typical UK domestic electricity, whereas a combined gas-and-electricity household total is nearer 11 000 kWh, and which you pick moves the answer by a factor of four.

Frequently Asked Questions

Is the Mass-Energy Equivalence Calculator free?

Yes, Mass-Energy Equivalence Calculator is totally free :)

Can I use the Mass-Energy Equivalence Calculator offline?

Yes, you can install the webapp as PWA.

Is it safe to use Mass-Energy Equivalence Calculator?

Yes, any data related to Mass-Energy Equivalence Calculator only stored in your browser (if storage required). You can simply clear browser cache to clear all the stored data. We do not store any data on server.

How does this mass-energy equivalence calculator work?

Every input is normalised to SI before any arithmetic runs — kilograms, joules, metres per second, kg·m/s — so a mass typed in MeV/c² and an energy typed in kilotons of TNT meet on the same footing. The active mode then applies one closed-form relation (E = mc², m = E/c², Q = Δm·c², E = γm₀c², E² = (pc)² + (m₀c²)²), and the conversion back to your chosen display unit happens only at the very last step. Nothing is ever computed from a rounded display value, so no two panels on the page can disagree.

Why is 1 u equal to 931.494 MeV, and why does that shortcut matter?

One atomic mass unit is 1.66053906660 × 10⁻²⁷ kg. Multiply by c² = 8.987551787 × 10¹⁶ m²/s² and you get 1.4924 × 10⁻¹⁰ J, which is 931.494 MeV once divided by the exact elementary charge. It matters because nuclear masses are tabulated in u to eight or nine decimal places, and a mass defect is a difference between two nearly equal numbers: working in u and multiplying by 931.494 at the end keeps every significant figure, whereas converting each mass to kilograms first throws most of them away to floating-point cancellation.

Why does the D–T fusion example give 17.590 MeV?

Deuterium (2.014102 u) plus tritium (3.016049 u) is 5.030151 u of reactants; helium-4 (4.002603 u) plus a neutron (1.008665 u) is 5.011267 u of products. The difference Δm = 0.018884 u, multiplied by 931.494 MeV/u, is 17.590 MeV per reaction. Scaled by Avogadro's number that is 1.697 × 10⁹ kJ per mole — about ten million times a chemical reaction — and 3.374 × 10¹⁴ J per kilogram of fuel, with just 0.375 % of the reactant mass actually converted.

Your relativistic momentum for a 0.511 MeV/c² electron at 0.99c differs from my textbook. Which is right?

The calculator returns p = 3.58616 MeV/c, and several sources print 3.5878. Work it through: γ = 1/√(1 − 0.99²) = 7.0888120, so p = γm₀v = 7.0888120 × 0.511 × 0.99 = 3.58616 MeV/c. The relativistic invariant confirms it independently — √(E² − (m₀c²)²) with the same source's own E = 3.6224 MeV also gives 3.58616. The 3.5878 figure is a propagated rounding error, and this tool implements the formula rather than the printed number.

What does the everyday-equivalence panel actually assume?

Each benchmark shows the figure it divides by, so you can audit it rather than take it on trust. A tonne of TNT is 4.184 × 10⁹ J and a kilowatt-hour is 3.6 × 10⁶ J — both conventional definitions, exact. The rest are stated assumptions: 34.2 MJ per litre of petrol, 15 kt for a Hiroshima-scale yield, 1 GJ per lightning stroke, and 2 700 kWh per household per year, which is typical UK domestic electricity. Counting household gas as well pushes the per-home figure nearer 11 000 kWh and divides the household count by about four, which is exactly why the basis is printed next to the number.

Why is relativistic mass shown but described as deprecated?

Because you will still meet it in older textbooks and it is useful to recognise, but working physicists abandoned it decades ago. Calling γm₀ a 'mass' suggests an object genuinely gets heavier and that Newton's second law still holds with it substituted in — neither is true, and the idea breaks down completely for a force applied along the direction of motion. The modern convention is that mass means rest mass, a single invariant number, and that all the velocity dependence sits in the energy and momentum instead.